Surds: Adding and Subtracting β A Comprehensive Guide
Surds: Adding and Subtracting
In this article, we will explore
- How to add and subtract surds
- A fundamental concept in mathematics that often appears in exams.
- Understanding surds and their manipulation is essential for solving various algebraic problems.
- We will delve into the rules governing the addition and subtraction of surds, simplify complex surds, tackle hard questions, and provide practice questions with answers to enhance your understanding.
They are very important in practicing questions for Algebra as well.
Here is one more link to practice a few extra questions: Maths Genie Surds Questions
What Are Surds?
- A surd is an irrational root of a rational number that cannot be simplified to remove the radical (square+ root) symbol.
- Surds are exact values and are left in root form because their decimal expansions are non-repeating and non-terminating.
Examples of Surds:
β3
β12
β50
These cannot be simplified to whole numbers or fractions, so they remain under the square root symbol.
Non-examples:
- β25 = 5 (since 5 squared equals 25)
- β36 = 6 (since 6 squared equals 36)
These are not surds because they simplify to rational numbers.
Adding and Subtracting Surds
The Basic Rule
- Surds can only be added or subtracted if they have the same irrational component (the same number under the square root sign).
- For example, you can add 2β7 + 4β7 because both surds contain β7
Why Can’t Different Surds Be Added Directly?
- Surds with different radicands (numbers under the square root) represent different irrational numbers. Since irrational numbers cannot be precisely calculated or compared without approximation, adding or subtracting surds with different radicands is not straightforward and generally cannot be simplified further.
Adding Surds
Rule: To add surds, they must have the same radicand. You add the coefficients (numbers in front of the surds) and keep the common surd.
Example 1
Add: 2β7 + 4β7
Solution:
- Both surds have β7
- Add the coefficients: 2 + 4 = 6
- Keep the common surd: 6β7
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Example 2
Add: 5β3 + 3β3
Solution:
- Both surds have β3
- Add the coefficients: 5 + 3 = 8
- Result: 8β3
Subtracting Surds
Rule: To subtract surds, they must have the same radicand. Subtract the coefficients and keep the common surd.
Example 1
Subtract: 5β6 – 2β6
Solution:
- Both surds have β6
- Subtract the coefficients: 5 – 2 = 3
- Result: 3β6
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Example 2
Subtract: 6β5 – β5
Solution:
- Remember that β5 has an implicit coefficient of 1.
- Subtract the coefficients: 6 – 1 = 5
- Result: 5β5
Simplifying Surds Before Adding or Subtracting
- Sometimes, surds need to be simplified before they can be added or subtracted. Simplifying surds involves expressing the surd in its simplest form by extracting square factors.
Steps to Simplify Surds
Step 1: Factorize the number inside the surd into its prime factors.
Step 2: Identify and extract square factors (pairs of identical factors).
Step 3: Simplify the surd by bringing out the square factors.
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Solved Example 1
Question: Simplify: 5β50 – 6β2
Solution:Β
Step 1: Simplify β50
Prime factorization of 50:
50 = 2 Γ 5 Γ 5
β50 = β(2 Γ 5 Γ 5)
Step 2:Β Extract square factors
- The pair of 5s can be taken out of the square root as a single 5.
- So, β50 = 5β2
Step 3: Substitute back into the expression
5β50 = 5 Γ 5β2 = 25β2
Step 4: Subtract 6β2
- Both surds now have β2
- Subtract the coefficients: 25 – 6 = 19
- Result: 19β2
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Solved Example 2
Question: Simplify: β20 + β45 – β12
Solution:Β
Step 1: Simplify each surd
Simplify β20
- Factorize: 20 = 2 Γ 2 Γ 5
- Extract the pair of 2s:
- β20 = 2β5
Simplify β45
- Factorize: 45 = 3 Γ 3 Γ 5
- Extract the pair of 3s:
- β45 = 3β5
SimplifyΒ β12
- Factorize: 12 = 2 Γ 2 Γ 3
- Extract the pair of 2s:
- β12 = 2β3
Step 2: Combine like terms
- Add 2β5 + 3β5 = 5β5
- The term 2β3 remains separate.
Final Answer: 5β5 – 2β3
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Solved Example 3
Question: Simplify: β27 + β45 – β12
Solution:Β
Step 1: Simplify each surd
Simplify β27
- Factorize: 27 = 3 Γ 3 Γ 3
- Extract the pair of 3s:
- β27 = 3β3
Simplify β45
- Factorize: 45 = 3 Γ 3 Γ 5
- Extract the pair of 3s:
- β45 = 3β5
SimplifyΒ β12
- Factorize: 12 = 2 Γ 2 Γ 3
- Extract the pair of 2s:
- β12 = 2β3
Step 2: Combine like terms:
- Add 3β3 – 2β3 = 1β3
- The term 3β5 remains separate.
Final Answer: β27 + β45 – β12 = 1β3 + 3β5
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Solved Example 4
Question: Simplify: 4β50 – 6β2
Solution:Β
Step 1: Simplify β50
- Prime factorization of 50:
50 = 2 Γ 5 Γ 5
β50 = β(2 Γ 5 Γ 5)
Step 2:Β Calculate:
4β50 = 4 Γ 5β2 = 20β2
- Subtract
6β2: 20β2 – 6β2 = 14β2
Answer: 14β2
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Solved Example 5
Question: Simplify: β75 – β27
Solution:Β
Step 1: Simplify each surd
Simplify β75
- Factorize: 75 = 25 Γ 3
- Extract the square root of 25:
- β75 = 5β3
Simplify β27
- Factorize: 27 = 3 Γ 3 Γ 3
- Extract the pair of 3s:
- β27 = 3β3
Step 2: Subtract:
5β3 – 3β3 = 2β3
Answer: 2β3
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Solved Example 6
Question: Simplify: β18 + β32 – β8
Solution:Β
Step 1: Simplify each surd
Simplify β18
- Factorize: 18 = 9 Γ 2
- Extract the square root of 9:
- β18 = 3β2
Simplify β32
- Factorize: 32 = 16 Γ 2
- Extract the square root of 16:
- β32 = 4β2
Simplify β8
- Factorize: 8 = 4 Γ 2
- Extract the square root of 4:
- β8 = 2β2
Step 2:Combine terms:
- Add 3β2 + 4β2 = 7β2
- Subtract 2β2:
7β2 – 2β2 = 5β2
Answer: 5β2
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Solved Example 7
Question: Simplify: β18 + β32 – β8
Solution:Β
Step 1: Simplify each surd
Simplify β18
- Factorize: 18 = 9 Γ 2
- Extract the square root of 9:
- β18 = 3β2
Simplify β32
- Factorize: 32 = 16 Γ 2
- Extract the square root of 16:
- β32 = 4β2
Simplify β8
- Factorize: 8 = 4 Γ 2
- Extract the square root of 4:
- β8 = 2β2
Step 2:Combine terms:
- Add 3β2 + 4β2 = 7β2
- Subtract 2β2:
7β2 – 2β2 = 5β2
Answer: 5β2
Multiply Surds
Understanding how to multiply surds is essential as it often comes up in simplifying expressions.
Rule for Multiplying Surds
βa Γ βb = β(a Γ b)
Example: Multiply: β5 Γ β20
Solution:
- Multiply under the radical:
β(5 Γ 20) = β100
- Simplify:
β100 = 10
Answer: 10
Dividing Surds
Dividing surds follows a similar principle.
Rule for Dividing Surds
- βa Γ· βb = β(a Γ· b), provided b is not zero.
Example Divide: β48 Γ· β3
Solution:
- Divide under the radical:
β(48 Γ· 3) = β16
- Simplify:
β16 = 4
Answer: 4
Conclusion
Understanding how to add and subtract surds is crucial for solving various mathematical problems, especially those encountered in exams. Remember:
- Only like surds (surds with the same radicand) can be added or subtracted directly.
- Simplify surds whenever possible to identify like terms.
- When multiplying or dividing surds, use the rules for operations under radicals.
By practicing these concepts and working through various problems, you will enhance your mathematical skills and be better prepared for exam questions on surds.
Practice Questions and Answers on Surds: Adding and Subtracting
Question 1: Simplify: 3β18 + 2β8
Question 2: Simplify: β75 – β27
Question 3: Simplify: 2β20 + 3β45
Question 4: Simplify: 5β12 – 3β27
Question 5: Simplify: β98 + β18
Question 6: Simplify: 4β32 – 2β8
Question 7: Simplify: β200 – 5β8
Question 8: Simplify: 6β125 + 4β80
Question 9: Simplify: 7β12 – 2β27
Question 10: Simplify: β8 + β18 + β32
Solutions
Question 1: Simplify: 3β18 + 2β8
Solution:
Step 1: Simplify Each Surd
β18 = 3β2
- Multiply: 3β18 = 3 Γ 3β2 = 9β2
β8 = 2β2
- Multiply: 2β8 = 2 Γ 2β2 = 4β2
Step 2: Add
9β2 + 4β2 = 13β2
Answer: 13β2
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Question 2: Simplify β75 – β27
Solution:
Step 1: Simplify Each Surd
β75 = 5β3
β27 = 3β3
Step 2: Subtract
5β3 – 3β3 = 2β3
Answer: 2β3
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Question 3: Simplify 2β20 + 3β45
Solution:
Step 1: Simplify Each Surd
β20 = 2β5
- Multiply: 2β20 = 2 Γ 2β5 = 4β5
β45 = 3β5
- Multiply: 3β45 = 3 Γ 3β5 = 9β5
Step 2: Add
4β5 + 9β5 = 13β5
Answer: 13β5
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Question 4: Simplify 5β12 – 3β27
Solution:
Step 1: Simplify Each Surd
β12 = 2β3
- Multiply: 5β12 = 5 Γ 2β3 = 10β3
β27 = 3β3
- Multiply: 3β27 = 3 Γ 3β3 = 9β3
Step 2: Subtract
10β3 – 9β3 = 1β3
Answer: 1β3
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Question 5: Simplify β98 + β18
Solution:
Step 1: Simplify Each Surd
- β98 = 7β2 (since 98 = 49 Γ 2)
- β18 = 3β2
Step 2: Add
7β2 + 3β2 = 10β2
Answer: 10β2
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Question 6: Simplify 4β32 – 2β8
Solution:
Step 1: Simplify Each Surd
β32 = 4β2
- Multiply: 4β32 = 4 Γ 4β2 = 16β2
β8 = 2β2
- Multiply: 2β8 = 2 Γ 2β2 = 4β2
Step 2: Subtract
16β2 – 4β2 = 12β2
Answer: 12β2
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Question 7: Simplify β200 – 5β8
Solution:
Step 1: Simplify Each Surd
- β200 = 10β2 (since 200 = 100 Γ 2)
β8 = 2β2
- Multiply: 5β8 = 5 Γ 2β2 = 10β2
Step 2: Subtract
10β2 – 10β2 = 0
Answer: 0
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Question 8: Simplify 6β125 + 4β80
Solution:
Step 1: Simplify Each Surd
β125 = 5β5
- Multiply: 6β125 = 6 Γ 5β5 = 30β5
β80 = 4β5
- Multiply: 4β80 = 4 Γ 4β5 = 16β5
Step 2: Add
30β5 + 16β5 = 46β5
Answer: 46β5
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Question 9: Simplify 7β12 – 2β27
Solution:
Step 1: Simplify Each Surd
β12 = 2β3
- Multiply: 7β12 = 7 Γ 2β3 = 14β3
β27 = 3β3
- Multiply: 2β27 = 2 Γ 3β3 = 6β3
Step 2: Subtract
14β3 – 6β3 = 8β3
Answer: 8β3
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Question 10: Simplify β8 + β18 + β32
Solution:
Step 1: Simplify Each Surd
- β8 = 2β2
- β18 = 3β2
- β32 = 4β2
Step 2: Add
2β2 + 3β2 + 4β2 = 9β2
Answer: 9β2
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