Sine and Cosine Rule
In this article, we will discuss:
Here is one more link to practice a few extra questions: Maths Genie Sine and Cosine Rule Questions
Where a, b, and c specify the lengths of the sides of the triangle, and A, B, and C denote the angles opposite the given sides.
Solved Example:
Question: Consider for example a triangle with sides A, B and C and angles A, B, and C, where side b is 8 units long and its angles A and B are 45 and 60 degrees, correspondingly. We want to find the length of side a.
Solution:
Since angle B is 60 degrees and side “b” is of 8 units
a / sin 45 = 8 / sin 60
We can rearrange the formula to isolate side a:
a = 8 x sin 45 / sin (60)
We can simplify the denominator of the sine function to get:
a = 8 x sin 45 / sin 60
a = 6.53 units
Thus, side a has the length of 6. 53 units.
Question 1: Suppose we have a triangle with sides x, y and z angles A, B, and C, where angle A is 30 degrees, angle B is 45 degrees, and side y is 10 units long. Determine the length of side x.
Answer :Step #1: Identify the angle and the opposite side of the triangle that you need to find the length of. In this case, we are looking for side x, which is opposite to angle A.
Step #2: Write down the sine rule formula:
x/sin A = y/sin B
Step #3: Substitute the known values of the other angle and its opposite side into the formula.
We know that angle B is 45 degrees, and side y is 10 units long.
x/sin 30 = 10/sin 45
Step #4: Rearrange the formula to make the unknown side the subject.
Reaarange the formula to isolate side x:
x = 10 x sin 30/sin 45
Step #5: Substitute the values and solve for the unknown side.
Simplify the expression:
x = 10 x 0.5/√2/2
x = 5/√2/2
x = 7.07 units
therefore, the length of side x is approximately 7.07 units.
Question 2: Consider a triangle with sides a, b and c and angles A, B and C. If angle A is 75 degrees, angle C is 40 degrees and side b is 12 units long, find the length of side a.
Answer :Solution:
Step #1: Identify the angle and the opposite side of the triangle that you need to find the length of. In this case, we are looking for side a, which is opposite to angle A.
Step #2: Write down the Sine Rule formula:
a/sin A = b/sin B
Step #3: Substitute the known values of the other angle and its opposite side into the formula.
We know that angle B is 180 – A – C = 65 degrees, and side b is 12 units long.
a/sin 75 = 12/sin 65
Step #4: Rearrange the formula to make the unknown side the subject.
Rearrange the formula to isolate side a:
a = 12 x sin 75/sin 65
Step #5: Substitute the values and solve for the unknown side.
Simplify the expression:
a = 12 x sin 75/sin 65
a = 13.11 units
therefore, the length of side a is approximately 13.11 units.
a2 = b2 + c2 – 2bc cos A
Where, a, b and c are the sides of the triangle, and A is the angle between the side b and c.
Solved Example:
Question: Find the length of the side “a” in a triangle with sides of lengths 5 and 7, and an included angle of 60 degrees.
Solution:
a² = b² + c² – 2bc cos A,
where a = unknown, b = 5, c = 7, and A = 60 degrees.
a² = 5² + 7² – 2(5)(7)cos 60°.
a² = 25 + 49 – 70 cos 60°.
a = sqrt(25 + 49 – 70 cos 60°).
a = sqrt(74 – 35) = sqrt(39) ≈ 6.25.
Therefore, the length of the unknown side “a” is approximately 6.25 units.
Question 1: Determine the length of side b in a triangle with sides of lengths 8 and 10, and an included angle of 75 degrees.
Answer :Step #1: Identify side b as the one to be found.
Step #2: Write the formula as
b2 = a2 + c2 – 2ac cos B,
where b is unknown, a = 8, c = 10, and B = 75°.
Step #3: Substitute the known values into the formula:
b2 = 82 + 102 – 2(8)(10) cos 75°.
Step #4: Simplify the equation by performing the arithmetic operations:
b2 = 64 + 100 – 160 cos 75°
Step #5: Take the square root of both sides to isolate the unknown side:
b = sqrt (64 + 100 – 160 cos 75°)
Step #6: Substitute the value of cos 75° and solve for the unknown side:
b = sqrt (164 – 160 cos 75°)
b = sqrt (164 + 160 sin 15°)
b = sqrt (164 + 160 x 0.2588)
b = sqrt (164 + 41.408)
b = √205.408
b = 14.33
therefore, the length of the unknown side b is approximately 14.33 units.
Question 2: Find the length of side c in a triangle with sides of lengths 12 and 15, and an included angle of 40 degrees.
Answer :Solution:
Step #1: Identify side c as the one to be found.
Step #2: Write the formula as
c2 = a2 + b2 – 2ab cos C,
where c is unknown, a = 12, b = 15, and C = 40 degrees.
Step #3: Substitute the known values into the formula:
c2 = 122 + 152 – 2(12)(15) cos 40°.
Step #4: Simplify the equation by performing the arithmetic operations:
c2 = 144 + 225 – 360 cos 40°
Step #5: Take the square root of both sides to isolate the unknown side:
c = sqrt (144 + 225 – 360 cos 40°)
Step #6: Substitute the value of cos 40° and solve for the unknown side:
c = sqrt (369 – 360 cos 40°)
c = sqrt (369 - 360 x 0.766)
c = sqrt (369 – 275.76)
c = √93.24
c = 9.65
Therefore, the length of the unknown side c is approximately 9.65 units.
Solved Example
Question: Find the measure of angle A in a triangle with sides of length 8, 10, and 12.
Solution:
cos A = (b² + c² – a²) / 2bc
cos A = (8² + 10² – 12²)/2(8)(10)
cos A = (64 + 100 – 144) / (2 x 8 x 10)
cos A = 0.025
A = cos-1(0.125) = 82.82 degrees
Therefore, the measure of angle A in the triangle is approximately 82.82 degrees.
To find the area of a triangle using the Sine Rule, follow these steps:
where a and b are the two sides and C is the angle between them.
Solved Example
Question: Consider a triangle with sides of length 5 and 7 and an angle of 60 degrees between them.
Solution:
A = 1/2 x ab x sin C.
A = 1/2 x 5 x 7 x sin 60,
A = 15.16
Therefore, the area of the triangle is approximately 15.16 square units.
Question 1: Consider a triangle with sides of length 12 and 15 and an angle of 30 degrees between them. Determine the area of the triangle by applying the Sine Rule.
Answer :Step #1: Utilize the formula for the area of a triangle using the Sine Rule:
A = ½ ab sin C.
Step #2: Substitute the given values into the formula, where a and b are the lengths of the sides, and C is the angle between them.
A = ½ x 12 x 15 x sin 30.
Step #3: Simplify the expression.
A = ½ x 12 x 15 x ½
A = 45
Therefore, the area of the triangle is 45 square units.
Question 2: In a triangle with sides of lengths 6 and 8 and an included angle of 75 degrees, calculate the area using the Sine Rule.
Answer :Solution:
Step #1: Utilize the formula for the area of a triangle using the Sine Rule:
A = ½ ab sin C.
Step #2: Substitute the given values into the formula, where a and b are the lengths of the sides, and C is the angle between them.
A = ½ x 6 x 8 x sin 75.
Step #3: Simplify the expression.
A = ½ x 6 x 8 x sin 75
A = 21.46
Therefore, the area of the triangle is approximately 21.46 square units.
Question 1: In triangle ABC the length of AC is 15cm. Angle ABC = 112° Angle BAC = 33° Work out the length of BC.
Question 2: Calculate the area of the triangle.
Question 3: Calculate the size of angle ABC.
Question 4: Calculate the size of the angle labelled y.