Quadratic Formula
In this article, we will discuss:
Here is one more link to practice a few extra questions: Maths Genie Quadratic Formula Questions
ax² + bx + c = 0,
where a, b, and c are constants, and x is the variable.
x = (-b ± √(b² – 4ac))/2a
b2 – 4ac
Which is part of the quadratic formula.
(a) If the discriminant is positive, the roots are distinct and real.
b2 – 4ac > 0
(b) If the discriminant is zero, the roots are equal and real.
b2 – 4ac = 0
(c) If the discriminant is negative, the roots are imaginary, and the equation has no real solutions.
b2 – 4ac < 0
Step #1: Write the quadratic equation in the form ax² + bx + c = 0.
Step #2: Identify the values of a, b, and c.
Step #3: Calculate the discriminant using the formula b² – 4ac.
Step #4: Determine the nature of the roots using the conditions for the discriminant.
Step #5: If the roots are distinct and real, substitute the values of a, b, and c in the quadratic formula, and simplify to get the solutions.
Step #6: If the roots are equal and real, substitute the values of a, b, and c in the quadratic formula, and simplify to get the solution.
Step #7: If the roots are imaginary, the quadratic equation has no real solutions.
Solved Example:
Question 1: Solve the quadratic equation x² – 3x – 10 = 0 using the quadratic formula.
Solution:
x² – 3x – 10 = 0
a = 1, b = -3, c = -10
x = (-b ± √b² – 4ac)/2a
x = (3 ± √(3² – 4(1)(-10))/2(1)
x = (3 ± √(49))/2
x1 = (3 + 7)/2 = 5
x2 = (3 – 7)/2 = -2
Therefore, the solutions to the equation x² – 3x – 10 = 0 are x = 5 and x = -2.
Question 2: Solve the quadratic equation 4x² – 5x + 1 = 0 using the quadratic formula.
Solution:
4x² – 5x + 1 = 0
a = 4, b = -5, c = 1
x = (-b ± √b² – 4ac)/2a
x = (5 ± √(5² – 4(4)(1))/2(4)
x = (5 ± √(9))/8
x1 = (5 + 3) / 8 = 1
x2 = (5 – 3) / 8 = 0.25
Therefore, the solutions to the equation 4x² – 5x + 1 = 0 are x = 1 and x ≈ 0.25.
Practice Questions
Question 1. Solve the quadratic equation x2 + 2x – 15 = 0 using the quadratic formula.
Answer : ( , )Step #1: Identify the coefficients a, b, and c in the quadratic equation, where
a = 1, b = 2, and c = -15.
Step #2: Substitute these values into the quadratic formula:
x = -b ± √(b2 - 4ac)/ 2a
Step #3: Plug in the values for a, b, and c:
x = -2 ± √(22 - 4(1)(-15)) / 2(1)
Step #4: Simplify the expression inside the square root:
x = -2 ± √(4 + 60) / 2
Step #5: Further simplify the expression inside the square root:
x = -2 ± √64 / 2
Step #6: Evaluate the square root:
x = -2 ± 8 / 2
Step #7: Simplify the expressions:
x1 = -2 + 8 / 2 = 3
x2 = -2 - 8 / 2 = -5
Question 2: Solve the quadratic equation x2 + 4x – 5 = 0 using the quadratic formula.
Answer : ( , )Solution:
Step #1: Identify the coefficients a, b, and c in the quadratic equation, where
a = 1, b = 4, and c = -5.
Step #2: Substitute these values into the quadratic formula:
x = -b ± √(b2 - 4ac)/ 2a
Step #3: Plug in the values for a, b, and c:
x = (-4 ± √(42 - 4(1)(-5))) / (2(1))
Step #4: Simplify the expression inside the square root:
x = (-4 ± √(16 + 20)) / 2
Step #5: Further simplify the expression inside the square root:
x = (-4 ± √36) / 2
Step #6: Evaluate the square root:
x = (-4 ± 6) / 2
Step #7: Simplify the expressions:
x1 = (-4 + 6) / 2 = 1
x2 = (-4 - 6) / 2 = -5
Question 1: Solve the quadratic equation 2x2 + 5x - 3 = 0.
Question 2: Solve the quadratic equation 2x2 + 7x + 3 = 0.
Question 3: Solve the quadratic equation 2x2 - 3x + 1 = 0.
Question 4: Solve the quadratic equation x2 - 6x + 8 = 0.
Question 5: Solve the quadratic equation 2x2 - 3x - 5 = 0.