Skip to content# Histogram Graph Questions and, Examples with Worksheet

## What is a Histogram?

## Histograms vs Bar Charts

## What is Frequency Density?

## How to find Frequency Density for Histograms

## Steps to draw a Histogram

## Steps to Interpret data from Histogram

**Histogram**

- Histograms are an important tool for visualizing data in a graphical format.
- A histogram is a type of graph that displays the frequency distribution of a dataset.
- It is commonly used in statistics and data analysis to summarize and interpret large amounts of information.

In this article, we will discuss:

**What is a Histogram?****We will explore the key features of histograms, their differences from bar charts, and how to draw and interpret them effectively.**

Here is one more link to practice a few extra questions: Maths Genie Histogram Questions

- A histogram is a type of graph that displays the frequency distribution of a dataset.
- It represents data using a series of bars, where each bar represents a specific range of values called a bin.
- The height of each bar corresponds to the frequency of data points that fall within that bin.

- Histograms are often confused with bar charts, but they are not the same thing.
- While both graphs use bars to represent data, the key difference is in the type of data they represent.
**Bar charts are used to compare data across different categories, while histograms are used to display frequency distributions of continuous data.**- In other words, bar charts are used for qualitative data, while histograms are used for quantitative data.

- Frequency density is a way of measuring the frequency of data in a histogram.
- It is calculated by dividing the frequency of each bin by the width of the bin.
- This gives the frequency density of the data within each bin, allowing us to compare the distribution of data across different bins.

**Frequency density = frequency/width of bin**

- To find the frequency density for a histogram, you need to divide the frequency of each bin by the width of the bin.
- The width of each bin is the range of values that it covers. For example, if a bin covers values from 20 to 30, its width would be 10.
- To calculate the frequency density for this bin, you would divide its frequency by 10.

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**Solved Example: **

**Question 1: ****Suppose we have collected data on the heights of 50 students in a ****class, and we want to create a histogram to represent this data. ****We group the heights into bins, with each bin representing a range of ****heights. Let’s say we have five bins with the following ranges:**

Solution:

We then count the number of students whose height falls within each bin.

Let’s say we get the following frequencies:

- 8 students in the 150-160 cm bin
- 12 students in the 160-170 cm bin
- 16 students in the 170-180 cm bin
- 9 students in the 180-190 cm bin
- 5 students in the 190-200 cm bin

To calculate the frequency density for each bin, we use the formula:

**Frequency density = frequency/width of bin**

For example, for the first bin, the width is 10 cm, so the frequency density is:

Frequency density for 150-160 cm

**bin = 8 / 10 **

**= 0.8**

Similarly, we can calculate the frequency density for each bin:

• Frequency density for 150-160 cm bin = 0.8

• Frequency density for 160-170 cm bin = 1.2

• Frequency density for 170-180 cm bin = 1.6

• Frequency density for 180-190 cm bin = 0.9

• Frequency density for 190-200 cm bin = 0.5

By using frequency density instead of frequency, we can compare the distribution of data across bins with different widths.

In this example, we can see that the distribution is highest in the 170-180 cm bin, which has the highest frequency density of 1.6.

To draw a histogram, follow these steps:

**Step #1:**Determine the range of the data and divide it into equal-sized bins.**Step #2:**Count the number of data points that fall within each bin.**Step #3:**Calculate the frequency density for each bin.**Step #4:**Draw the x-axis with the range of the data and the y-axis with the frequency density.**Step #5:**Draw a rectangle for each bin with a height corresponding to its frequency density.

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**Solved Example**

**Question: ****Let’s say we have the following data set representing the scores of ****30 students in a math test: ****80, 78, 90, 85, 92, 84, 77, 85, 88, 80, 75, 72, 85, 90, 88, 92, 78, 82, 86, ****90, ****82, 83, 85, 88, 92, 89, 86, 80, 78, 85. We aim to construct a histogram to visually represent the score distribution.**** ****Here’s how we can do it:**

Solution:

**Step #1:**Determine the range of the data and divide it into equal-sized bins.The range of the data is 20 (92-72).

We can divide it into 5 bins of size 5:

**Step #2:**Count the number of data points that fall within each bin.Using the bins, we created in step #1,

we can count the number of scores that fall within each bin:

**Step #3:**Calculate the frequency density for each bin.To calculate the frequency density for each bin,

we divide the frequency (number of scores) by the width of the bin (4):

**70-74: 1/5 = 0.2****75-79: 5/5 = 1****80-84: 7/5 = 1.4****85-89: 11/5 = 2.2****90-94: 6/5 = 1.2**

**Step #4:**Draw the x-axis with the range of the data and the y-axis with the frequency density. We draw the x-axis with the bins we created in step #1 and the y-axis with the frequency

- When interpreting histograms, it is important to note that the frequency density (y-) axis does not directly tell us the frequency.
- Instead, the frequency is proportional to the area of the bar.

**To find the frequency for each bin, you can use the formula frequency equals area.**

- This means that the frequency is equal to the area of the bar, which can be determined by finding the product of the width and height of the bar.
- However, there may be cases where the frequency is only proportional to the area of the bar, in which case you would need to use the formula frequency equals k cross times area.

- Here, k is a constant that needs to be determined from other information given in the question.
- If you need to estimate the frequency of a part of a bar or class interval within a histogram, you can find the area of the relevant part of the bar and then use the formula mentioned above to find the frequency

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**Solved Example**

**Question: ****The table below and its corresponding histogram show the mass, in kg, ****of ****some newborn bottlenose dolphins.**

**(a) Use the table and histogram to find the value of k in the formula**

**(b) Estimate the number of dolphins whose weight is greater than 13 kg.**

Solution:

**(a) **

Start by finding the frequency density in terms of k – add two columns to the table, one for class width, one for frequency density

We can use either of the two intervals that feature both in the table and on the histogram to find the value of k

Using the first bar

**Check using the other (2 ^{nd}) bar to check: 7.5k = 3.75, k = 0.5**

**(b) Estimate the number of dolphins whose weight is greater than 13 kg.**

**Solution:**

We can see from the table that there are 6 dolphins in the interval 15 ≤ m <30.

So we need to estimate the number of dolphins that are in the interval 13≤ m <15.

For 13≤ m <15, the histogram shows the frequency density is 1.5 and we found the value of k in part(a).

Using the formula given in the question

So the total number of can be estimated by

**6 + 6 = 12**

**There are approximately 12 dolphins with a weight greater than 13kg**