In this lesson, we will discuss what Fractional Indices are, how they are simplified, and the logic behind negative fractional indices. We will also walk through step-by-step examples to help you understand the concepts and solve some GCSE Past Paper Questions
Indices (also known as exponents) allow us to write repeated multiplication in a simpler way. For example:
This idea is fundamental to working with more advanced topics like fractional indices.
Fractional indices are Exponents written as fractions, for example,
xm/n
They combine the ideas of Powers and Roots into a single operation:
This means you take the n-th root of x first, then raise the result to the power of m.
Which is the same as raising the n-th root of x to the power m
Some examples of fractional exponents that are widely used are given below:
Step #1: Identify the Fractional Exponent
Step #2: Rewrite in Root Form
Convert
into
Step #3: Find the n-th Root
Step #4: Apply the Power
Step #5: Combine and Simplify
Problem: Simplify:
Solution:
Step #1: Identify the Exponent
2/3 means power = 2 and root = 3
Step #2: Rewrite as a Root First
Step #3: Find the Cube Root 2161/3
216 = 23 × 33
so,
Step #4: Apply the Power m = 2
(6)2 = 36
Step #5: Final Answer
2162/3 = 36
Using these clear steps—and prime factorization when you’re unsure about the root—makes fractional indices much easier to handle.
In the previous example, 216 was a perfect cube—making it straightforward to take the cube root.
However, not all numbers factor into perfect powers so neatly.
Let’s look at another example with 250, which will result in a simplified radical rather than a whole number.
Problem: Simplify:
Solution:
Step #1: Identify the Exponent
2/3 means power = 2 and root = 3
Step #2: Rewrite in Root Form
Step #3: Prime-Factorize 250
250 = 2 × 125 = 2 × 53
so,
Step #4: Apply the Power m = 2
Step #5: Final Answer
(250)2/3 = 25 ∛4
If you prefer a decimal approximation, then ∛4 ≈ 1.5874
so,
25 × 1.5874 ≈ 39.685
Video Tutorial on Fractional Indices
Question 1: Simplify: 1252/3
Question 2: Simplify: 643/2
Question 3: Simplify: 5002/3
Question 4:Simplify: 324/5
Question 5: Simplify: 813/4
Question 6: Simplify: 7292/3
Question 7: Simplify: 1283/7
Question 8: Simplify: 10002/3
Question 9: Simplify: 165/4
Question 10: Simplify: 2434/5
Question 1:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Prime-Factorize 125
Step #4: Apply the Power (2)
Step #5: Final Result
1252/3 = 25
Question 2:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Prime-Factorize 64
Step #4: Apply the Power (3)
Step #5: Final Result
643/2 = 512
Question 3:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Prime-Factorize 500
Step #4: Apply the Power (2)
Step #5: Final Result
5002/3 = 25 × ∛4
Question 4:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Fifth Root of 32
Step #4: Apply the Power (4)
Step #5: Final Result
324/5 = 16
Question 5:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Fourth Root of 81
Step #4: Apply the Power (3)
Step #5: Final Result
813/4 = 27
Question 6:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: ∛729
Step #4: Apply the Power (2)
Step #5: Final Result
7292/3 = 81
Question 7:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Seventh Root of 128
Step #4: Apply the Power (3)
Step #5: Final Result
1283/7 = 8
Question 8:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Cube Root of 1000
Step #4: Apply the Power (2)
Step #5: Final Result
10002/3 = 100
Question 9:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: Fourth Root of 16
Step #4: Apply the Power (5)
Step #5: Final Result
165/4 = 32
Question 10:
Solution:
Step #1: Identify the Exponent
Step #2: Rewrite in Root Form
Step #3: F Fifth Root of 243
Step #4: Apply the Power (4)
Step #5: Final Result
2434/5 = 81