Factorising Quadratics
“a” is the coefficient of the x2 term,
“b” is the coefficient of the x-term;
“c” represents the constant term.
The expression with the form (x2 + bx + c) can be done by two brackets as (x + d)(x + e).
Expression vs. Equation:
Method #1: Factorising “by inspection”
Identify coefficients:
In this example, b is 6, and c is 9.
Find two numbers:
3 x 3 = 9
and
3 + 3 = 6
Write in brackets:
In fact, through observation, you can see that this expression can be factorized either as (x + 3)(x + 3) or as (x + 3)2.
Method 2: Factorising “by grouping”
Identify coefficients:
Find two numbers:
(-6) x 2 = -12
and
(-6) + 2 = -4
Rewrite the middle term:
x2 – 6x + 2x – 12
Group and factorize:
(x(x – 6) + 2(x – 6))
Factor out common factors:
Factor out (x – 6):
(x – 6)(x + 2).
Hence, you can factor this x2 – 4x – 12 as (x – 6)(x + 2).
Solved Example:
Question 1: Factorize x2 – 13x + 36.
Solution:
The quadratic expression is x2 -13x + 36.
The coefficient, b is -13 and c = 36.
Seek a pair of numbers that, when multiplied, equal to c (36) and when added, equal to b (-13).
The numbers are -9 and -4 since
(-9) x (-4) = 36
and
(-9) + (-4) = -13
Express the midterm of the quadratic expression with the two factors determined through the process of factorization
x2 – 9x – 4x + 36
Group the terms in pairs and extract the common factor from each pair.
Factor out x from the first two terms and -4 from the last two terms:
(x(x – 9) -4(x – 9))
See that we have a common term for both expressions, that is, (x – 9).
Factor out (x – 9):
(x – 9)(x – 4).
So, by grouping, you can factorize x2 – 13x + 36 as (x – 9)(x – 4).
Question 1. Factorize x2 + 7x + 12
Answer : ( )( )The quadratic expression is x2 + 7x + 12
The coefficient, b is 7, and c is 12.
Look for a pair of numbers that multiply to c (12) and add up to (7).
The numbers are 3 and 4 because
3 x 4 = 12 and 3 + 4 = 7
Rewrite the middle term of the quadratic expression using the two numbers found.
x2 + 3x + 4x + 12
Group the terms into pairs and factor out the common factor from each pair.
Factor out x from the first two terms and 4 from the last two terms:
(x(x + 3) +4(x + 3))
Notice that both terms now have a common factor of (x + 3).
Factor out (x + 3):
(x + 3)(x + 4).
So, by grouping, you can factorize x2 + 7x + 12 as (x + 3)(x + 4).
Question 2: Factorize x2 + 8x + 15
Answer : ( )( )Solution:
The quadratic expression is x2 + 8x + 15
The coefficient, b is 8, and c is 15.
Look for a pair of numbers that multiply to c (15) and add up to (8).
The numbers are 3 and 5 because
3 x 5 = 15 and 3 + 5 = 8
Rewrite the middle term of the quadratic expression using the two numbers found.
x2 + 3x + 5x + 15
Group the terms into pairs and factor out the common factor from each pair.
Factor out x from the first two terms and 5 from the last two terms:
(x(x + 3) +5(x + 3))
Notice that both terms now have a common factor of (x + 3).
Factor out (x + 3):
(x + 3)(x + 5).
So, by grouping, you can factorize x2 + 8x + 15 as (x + 3)(x + 5).
Solved Example:
Question: Factorize 5x2 – 13x – 6
Solution:
5 x (-6) = -30
Write out the factor pairs of -30 in order:
(-1,30), (-2, 15), (-3, 10), (-5, 6).
The pair is (-15,2) because (-15) + 2 = -13
5x2 – 15x + 2x – 6
5x2 – 15x and 2x – 6.
Fully factorize each half:
5x(x – 3) and 2(x – 3).
(5x + 2)(x – 3)
So, the solution to 5x2 -13x -6 by factorizing into double brackets is (5x + 2) (x – 3)
Question 1. Factorize 2x2 + 9x + 10
Answer : ( )( )The quadratic expression is 2x2 + 9x + 10.
The coefficient of x2 (a) is 2, the coefficient of x (b) is 9, and the constant term (c) is 10.
Multiply the coefficient of x2 by the constant term:
2 x 10 = 20
Identify factor pairs of 20 that add up to the coefficient of x(9).
The pair is (5, 4) because 5 x 4 = 20 and 5 + 4 = 9
Rewrite the middle term using the factor pairs:
2x2 + 5x + 4x + 10
Group the terms in pairs and extract the common factor from each pair:
x(2x + 5) + 2(2x + 5).
Factor out the common factor (2x + 5)
(2x + 5) (x + 2)
So, the quadratic expression 2x2 + 9x + 10 factors into (2x + 5)(x + 2).
Question 2: Factorize 5x2 + 26x + 5
Answer : ( )( )Solution:
The quadratic expression is 5x2 + 26x + 5.
The coefficient of x2 (a) is 5, the coefficient of x (b) is 26, and the constant term (c) is 5.
Multiply the coefficient of x2 by the constant term:
5 x 5 = 25
Identify factor pairs of 25 that add up to the coefficient of x(26).
The pair is (1, 25) because 1 x 25 = 25 and 1 + 25 = 26
Rewrite the middle term using the factor pairs:
5x2 + x + 25x + 5
Group the terms in pairs and extract the common factor from each pair:
x(5x + 1) + 5(5x + 1).
Factor out the common factor (5x + 1)
(5x + 1) (x + 5)
So, the solution of 5x2 + 26x + 5 by factorizing is (5x + 1)(x + 5)
Factorising quadratics is one of the important skills for a deeper understanding of algebraic statements.
Comprehension of factorisation entails a unique mathematical instrument that can be used in numerous disciplines.
This skill is varied from basic to creative mathematics.
Question 1: Factorize x2 + 10x + 25
Question 2: Factorize x2 + 9x + 14
Question 3: Factorize 2x2 + 17x + 36
Question 4: Factorize 5x2 + 62x + 24
Question 5: Factorize 7x2 + 10x + 3